int aaa;
int bbb,ccc;
int values[10];

task main()
{
  aaa = 10;
  bbb = 20 * 5;
  ccc = bbb;
  ccc /= aaa;
  ccc -= 5;         
  aaa = 10 * (ccc + 3); // aaa is now equal to 80
  values[0] = aaa;
  values[1] = bbb;
  values[2] = aaa*bbb;
  values[3] = ccc;
}
